?Suppo se that in the same Atwood setup another string is attached to the bottom

Question

?Suppose that in the same Atwood setup another string is attached to the bottom of m1 and a constant force f is applied, retarding the upward motion of m1. If m1 = 5.90 kg and m2 = 11.80 kg, what value of f will reduce the acceleration of the system by 50%?

?Suppose that in the same Atwood setup another string is attached to the bottom of m1 and a constant force f is applied, retarding the upward motion of m1. If m1 = 5.90 kg and m2 = 11.80 kg, what value of f will reduce the acceleration of the system by 50%?

Explanation / Answer

initail case

11.80 - T = 11.8*a

T -5.9*9.8 = 5.9*a

a = 3.266

when force applied on m1

11.8*9.8 - T = 11.8*a

T -f - 5.9*9.8 = 5.9*a

11.8*9.8 - 5.9*9.8 -f = (11.8+5.9)*a
but given a =3.266/2 = 1.633

we get f = 28.9159 N

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