(a) A parallel-plate capacitor has plates of area A = 2.10 x 10-2 m2, separated
ID: 1281151 • Letter: #
Question
(a) A parallel-plate capacitor has plates of area A = 2.10 x 10-2 m2, separated by a distance d = 1.50 mm. Charges Q = ±15.0 nC are placed on the plates of the capacitor. Suppose that a vacuum fills the region between the plates. Determine the magnitude of the free surface charge, eta, on the capacitor plates, and the magnitude of the vacuum field
Eta0 between the plates. 714 nC/m^2 = Correct: Your answer is correct.
E0 between the plates. 80.7 kV/m = Correct: Your answer is correct.
(b) Suppose instead that a dielectric material fills the region between the plates, resulting in a field between the plates of magnitude Enet = 40.0 kV/m. This net electric field is the resultant of the field Eo due to the free surface charges on the capacitor in (a), and a polarization field, Ep, due to bound surface charges induced on the dielectric. Determine the magnitude of the polarization field, and the magnitude of the polarization surface charge p induced on the dielectric.
(c) What is the dielectric constant of the material?
ONLY NEED HELP WITH B AND C
Explanation / Answer
B. E = Eocos theta
cos theta = 40/80.7
cos theta = 0.495
theta = 60.28 deg
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C. E = Eo/K
K = 80.7/40
K = 2 is the dielectric constnt
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