Determine the stretch in each spring for for equilibrium of the 2.4-kg block. Th

Question

Determine the stretch in each spring for for equilibrium of the 2.4-kg block. The springs are shown in the equilibrium position.

Determine the stretch in each spring for for equilibrium of the 2.4-kg block. The springs are shown in the equilibrium position.

Determine the stretch in spring AC.

xAC =

Determine the stretch in spring AB.

xAB = Determine the stretch in each spring for for equilibrium of the 2.4-kg block. The springs are shown in the equilibrium position. Determine the stretch in each spring for for equilibrium of the 2.4-kg block. The springs are shown in the equilibrium position. Determine the stretch in spring AC. xAC = Determine the stretch in spring AB. xAB =

Explanation / Answer

Fad = mg = 2.4 x 9.81 = 23.54 N

at point A.

Fac cos45 = Fab x4 / 5 ( balance in horizontal)

Fab = 1.13 Fac

and Fac sin45 + Fab*3 / 5 = 23.54   

Fac sin45 + 1.13Fac x 3 /5 = 23.54

Fac = 16.98 N   
F = kx

so x = 16.98 / 20 = 0.85 m

Fab = 1.13 x 16.98 = 19.19 N

so x = 19.19 / 30 = 0.64 m

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