A 60g ball is tied to the end of a 50 -cm-long string and swung in a vertical ci

Question

A 60g ball is tied to the end of a 50 -cm-long string and swung in a vertical circle. The center of the circle, as shown in the figure,(Figure 1) is 150 cm above the floor. The ball is swung at the minimum speed necessary to make it over the top without the string going slack.

A 60g ball is tied to the end of a 50 -cm-long string and swung in a vertical circle. The center of the circle, as shown in the figure,(Figure 1) is 150 cm above the floor. The ball is swung at the minimum speed necessary to make it over the top without the string going slack. a) If the string is released at the instant the ball is at the top of the loop, how far to the right does the ball hit the ground?

Explanation / Answer

a) v^2/r = g

v = sqrt(g*r)

= sqrt(9.8*0.5)

= 2.213 m/s

let t is the time taken to hit the ground.

h = 0.5*g*t^2

t = sqrt(2*h/g)

= sqrt(2*2/9.8)

= 0.639 s

so, x = v*t

= 2.213*0.639

= 1.414 m <<<<<<<<---------Answer

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