In the (Figure 1) the coefficient of static friction between mass mA and the tab

ID: 1282838 • Letter: I

Question

In the (Figure 1) the coefficient of static friction between mass mA and the table is 0.45, whereas the coefficient of kinetic friction is 0.19. Ignore masses of the cord and the (frictionless) pulley. What minimum value of mA will keep the system from starting to move? What value of mA will keep the system moving at constant speed?

Explanation / Answer

to system at rest.

T = mb .g = 2 x 9.8 = 19.6 N

and friction = u.ma.g = 19.6

0.45 x m x 9.1 = 19.6

m = 4.44 kg

to keep system moving with constant velocity .

kinetic friction = 19.6

0.19 x m x 9.8 = 19.6

m =10.53 kg

Navigate

In the (Figure 1) position-versus-time graph for a collision between two carts o

In the (Figure 1) the coefficient of static friction between mass m_A and the ta

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.

In the (Figure 1) the coefficient of static friction between mass mA and the tab

Question

Explanation / Answer

Related Questions

Navigate