Exercise 6.36 A 1.30kg box and a 3.80kg box on a perfectly smooth horizontal flo

Question

Exercise 6.36

A 1.30kg box and a 3.80kg box on a perfectly smooth horizontal floor have a spring of force constant 180N/m compressed between them. The initial compression of the spring is 8.00cm .

Part A

Find the acceleration of 1.30kg box the instant after they are released.

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Part B

Find the acceleration of 3.80kg box the instant after they are released.

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Exercise 6.36

A 1.30kg box and a 3.80kg box on a perfectly smooth horizontal floor have a spring of force constant 180N/m compressed between them. The initial compression of the spring is 8.00cm .

Part A

Find the acceleration of 1.30kg box the instant after they are released.

a =   m/s2  

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Part B

Find the acceleration of 3.80kg box the instant after they are released.

a =   m/s2  

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Explanation / Answer

Spring is stretched by 8 cm

therefore restoring force by the spring on each of the 2 blocks will be

F = kx = 180*0.08 = 14.4 N

therefore

acceleration of 1.30kg box the instant after they are released = 14.4/1.3 = 11.08 m/s^2 (Answer)

acceleration of 3.80kg box the instant after they are released = 14.4/3.8 = 3.79 m/s^2 (Answer)

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