A small rock with mass 0.235 kg is fastened to a massless string with length 0.8

Question

A small rock with mass 0.235 kg is fastened to a massless string with length 0.830 m to form a pendulum. The pendulum is swinging so as to make a maximum angle of 40.0 degrees with the vertical. Air resistance is negligible.

A.What is the speed of the rock when the string passes through the vertical position?

B.What is the tension in the string when it makes an angle of 40.0 degrees with the vertical?

C.What is the magnitude of the acceleration of the rock when it makes an angle of 40.0 degrees with the vertical?

D.What is the tension in the string as it passes through the vertical?

Explanation / Answer

A.
The kinetic energy in the vertical position equals the potential energy at 40 degree

PE = m*g*l*(1 - cos40)

Kinetic energy = 0.5*m*v

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