(b) What angle does the force vector make with the positive x axis? =__ F x = __
ID: 1282961 • Letter: #
Question
(b) What angle does the force vector make with the positive x axis?
=__
Fx = __ N Fy = __ N Fz = __ N A particle with positive charge q = 1.28 10-18 C moves with a velocity k hat) V/m. Fx = __ N Fy = __ N Fz = __ N (b) What angle does the force vector make with the positive x axis? j hat ? 5i hat ? E with arrow = (2k hat) T and j hat + i hat + 5B with arrow = (3k hat) m/s through a region where both a uniform magnetic field and a uniform electric field exist. (a) Calculate the total force on the moving particle, taking j hat ? i hat + 5v with arrow = (3Explanation / Answer
F = qE + q(v * B)
= [ (1.28 * 10-18) (2i - j - 5k)] +[(1.28 * 10-18) (3i + 5j - k)(3i + 5j + k)]
= (1.28 * 10-18) (11i +24 j - 5k)
= (14.08 * 10-18)i + (30.72 * 10-18)j - (6.4 * 10-18)k
Fx = 14.08 * 10-18 N
Fy = 30.72 * 10-18 N
Fz = - 6.4 * 10-18 N
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Fx = F cos theta
theta = cos-1 [Fx / sqrt [Fx2 + Fy2 + Fz2]]
= cos-1 [(14.08 * 10-18) / sqrt [(14.08 * 10-18)2 + (30.72 * 10-18)2 + (6.4 * 10-18)2]]
= 65.83 deg
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