A sudden gust of wind dislodges another acorn from the branch of a different oak

Question

A sudden gust of wind dislodges another acorn from the branch of a different oak tree (Quercus velutina) imparting a horizontal initial velocity of 10 ms. The acorn lands after traving a horizontal distance of 15 m. How high was the branch from which it fell? (Assume the wind stops when the acorn is dislodged and neglect air resistance during the fall) A sudden gust of wind dislodges another acorn from the branch of a different oak tree (Quercus velutina) imparting a horizontal initial velocity of 10 ms. The acorn lands after traving a horizontal distance of 15 m. How high was the branch from which it fell? (Assume the wind stops when the acorn is dislodged and neglect air resistance during the fall) A sudden gust of wind dislodges another acorn from the branch of a different oak tree (Quercus velutina) imparting a horizontal initial velocity of 10 ms. The acorn lands after traving a horizontal distance of 15 m. How high was the branch from which it fell? (Assume the wind stops when the acorn is dislodged and neglect air resistance during the fall)

Explanation / Answer

Now initial horizontal velocity = 10m/s

This velocity remains same as there is no external force acting in the horizontal direction therefore
horizontal distance travelled = v*t = 10*t = 15
therefore
t = 1.5 seconds

Now initial vertical velocity component = 0

a = -9.8
therefore
using s= ut + 1/2at^2 = 1/2*-9.8*1.5*1.5 = 11.025 meter (Answer)

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