A positively charged particle with initial velocity v = 17.0 x 10 5 m/s travels

Question

A positively charged particle with initial velocity v = 17.0 x 105 m/s travels straight through chamber where we have both an electric field and a magnetic field and exits the other side.

a) What is the direction of the needed magnetic field?

b) What is in Tesla the magnitude of the needed magnetic field if the electrical field magnitude is |E|=0.31 x 105 N/C?

After exciting the chamber, the particle enters a region where we have only a magnetic field that is pointing into the screen and has a magnitude |B2|=2.55 T. It is observed that the particle follows a curved path of radius R=360 mm.

c) What is in Kilograms the mass of the particle? Assume that the particle has a charge of 1.6 x 10-19 C.

A positively charged particle with initial velocity v = 17.0 x 10^5 m/s travels straight through chamber where we have both an electric field and a magnetic field and exits the other side. a) What is the direction of the needed magnetic field? downwards upwards into the page out of the page towards the left towards the right b) What is in Tesla the magnitude of the needed magnetic field if the electrical field magnitude is |E|=0.31 x 10^5 N/C? After exciting the chamber, the particle enters a region where we have only a magnetic field that is pointing into the screen and has a magnitude |B2|=2.55 T. It is observed that the particle follows a curved path of radius R=360 mm. c) What is in Kilograms the mass of the particle? Assume that the particle has a charge of 1.6 x 10^-19^5 C.

Explanation / Answer

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a. magnetic filed will be out of the page
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b. apply E = BV

so B = 0.31e5/(17e5)

B = 18.23 mT
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C.
apply mg = Eq

mass m = 0.31e5* 1.6e-19/(9.8)

mass = 5.511*10^-15 Kgs
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