Suppose that the flow into the network of bulbs A, C and D is 1 unit of flow . 1

Question

Suppose that the flow into the network of bulbs A, C and D is 1 unit of flow.

1. How large is the flow through bulb A: equal to unit, greater than unit or less than unit? Explain. 2. How large is the flow through bulb C: equal to unit, greater than unit or less than unit? Explain. 3. How large is the flow through bulb D: equal to unit, greater than unit or less than unit? Explain .

4. If the flow out of the network of bulbs B and E is of size 1 unit, what is the flow into & out of the network of bulbs A, C and D? Explain.

In general, Compare the sizes of the flow through bulb A, bulb C and bulb D.

Suppose that the flow into the network of bulbs A, C and D is 1 unit of flow. 1. How large is the flow through bulb A: equal to ½ unit, greater than ½ unit or less than ½ unit? Explain. 2. How large is the flow through bulb C: equal to ½ unit, greater than ½ unit or less than ½ unit? Explain. 3. How large is the flow through bulb D: equal to ½ unit, greater than ½ unit or less than ½ unit? Explain . 4. If the flow out of the network of bulbs B and E is of size 1 unit, what is the flow into & out of the network of bulbs A, C and D? Explain. In general, Compare the sizes of the flow through bulb A, bulb C and bulb D.

Explanation / Answer

Given the flow through

network with elements A, C, D is 1

let All elements have 1unit resistance

1)

since C, D are in series and a is in parellel with C,D

currunt throught a is double the currunt through C,D

let x be the currunt through C

then X + 2X = 1 => x = 0.33

hence currunt through A = 2X = 0.66 i.e greater than 1/2 unit

2) since C and D are in series

currunt throught them will be same

currunt through C = X =0.33 less tha 1/2 unit

3) currunt through D = X = 0.33 less than 1/2 unit

4) currunt through C = currunt through D = 1/2 (currunt through D)

Related Questions

Navigate

• Browse (All)
• Browse S
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.