b) Find the gravitational force between them if the distance is doubled to 6.0x1

Question

b) Find the gravitational force between them if the distance is doubled to 6.0x10^12 m. c) Divide the answer for part a) by the answer in part b). What do you get? Could you have predicted this before? 4. Assuming the stars are in a perfectly circular orbit, how long will it take them to complete one period? (Hint; in Kepler's third law, replace m, with 2 m,.) 5. A person sitting on a sled is at the top of a 20-m hill of snow. Assuming there is no loss of energy to friction, answer the following questions. a) What type of energy is present initially and how much of it is there?

Explanation / Answer

if the distance between them is doubled, then

F' = Gmm/r'2

= (6.67 x 10-11 ) ( 2 x 1030) ( 2 x 1030)/(6 x 1012)2

= 3.7 x 10-6 N

Dividing the answer for part a and part b we get the ration to be 4

This means that keeping other things constant if we double the distance between the stars the gravitational force between them will decrease by a factor of 4

5. a

m = 40kg

h= 20 m

g = 9.8 m/s2

The energy possesed by the person will be potential energy.

This energy is equal to mgh = 40 x 20 x 9.8 = 7840 J

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