Question 7 In the circuit below, the capacitor is initially uncharged. When the

Question

Question 7 In the circuit below, the capacitor is initially uncharged. When the switch is closed, the bulb starts bright, and gets brighter and brighter slowly for some time and finally stays the same. . starts dim and gets brighter and brighter as more and more charge accumulates on the capacitor . starts bright and remains the same because the circuit is closed. never gets brighter because the capacitor Is an Insulator. . starts bright, then gets dimmer and dimmer slowly until it goes out. Question 8 In Question 7 how would your observations be changed if the capacitor were twice as large? The bulb would start brighter, and stays the same. The bulb would start bright, then gets dimmer and dimmer for a short time and finally goes out. The bulb would start dim, and gets brighter in a shorter time. The bulb would still not get brighter because the capacitor is an Insulator. The bulb would start bright, and gets brighter and brighter for some time and finally stays the same. The bulb would start bright, then gets dimmer and dimmer for a longer time and finally goes out.

Explanation / Answer

Questin 7

6) starts bright and then gets dimmer and dimmer until it goes out

Question 8

6. The bulb would start bright , then gets dimmer and dimmer for a longer time and finally goes out

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