golf ball strikes a hard, smooth floor at an angle of 24.1 and, as the drawing s
ID: 1284310 • Letter: G
Question
golf ball strikes a hard, smooth floor at an angle of 24.1 and, as the drawing shows, rebounds at the same angle. The mass of the ball is 0.0641 kg, and its speed is 53.4 m/s just before and after striking the floor. What is the magnitude of the impulse applied to the golf ball by the floor? (Hint: Note that only the vertical component of the ball's momentum changes during impact with the floor, and ignore the weight of the ball.)
golf ball strikes a hard, smooth floor at an angle of 24.1 ? degree and, as the drawing shows, rebounds at the same angle. The mass of the ball is 0.0641 kg, and its speed is 53.4 m/s just before and after striking the floor. What is the magnitude of the impulse applied to the golf ball by the floor? (Hint: Note that only the vertical component of the ball's momentum changes during impact with the floor, and ignore the weight of the ball.)Explanation / Answer
As the angle and speed before and after collision is same. So, it is elastic and momentum change occurs in y-dir. only.
Impulse= shange in momentum in y-dir.= 2mv sin(24.1)o
= 2.795 kgm/s
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