The switch in the figure has been open for a long time. It is closed at t = 0s.

Question

The switch in the figure has been open for a long time. It is closed at t = 0s.

Part A

What is the current through the battery immediately after the switch is closed?

Part B

What is the current through the battery after the switch has been closed a long time?

The switch in the figure has been open for a long time. It is closed at t = 0s. Part A What is the current through the battery immediately after the switch is closed? Part B What is the current through the battery after the switch has been closed a long time?

Explanation / Answer

The Inductor in the circuit will act as an open circuit immeadiately after the switch is closed and acts as a short circuit when the switch is closed for a long time. Hence,

a) current is V/Req=10/20 = 0.5Amps

b) current is V/Req=10/(equivalent resistance of 20ohm resistors in parallel)=10/10 = 1 Amp.

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