The gravitational pull of the earth on an object is inversely proportional to th

Question

The gravitational pull of the earth on an object is inversely proportional to the square of the distance of the object from the center of the earth. At the earth's surface this force is equal to the object's normal weight mg where g = 9.8 m/s^2 , and at large distances, the force is zero.


A) If a 30,000-kg asteroid falls to earth from a very great distance away, what will be its minimum speed as it strikes the earth's surface? You can ignore the effects of the earth's atmosphere.


B) What will be its minimum speed as it strikes the earth's surface?

Explanation / Answer

potential energy differcne = GMe x 30000 / Re = 30000 x 6.24 x 10^7 J

thats is converted in K.E.

30000v^2 /2 = 30000 x 6.24 x 10^7

v = 7901.63 m/s

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.