Friction Quiz MULTIPLE CHOICE, Choose the one alternative that best completes th

Question

Friction Quiz MULTIPLE CHOICE, Choose the one alternative that best completes the statement or answers the question. 1) A packing crate slides down an inclined ramp at constant velocity. Thus we can deduce that 1) A) a frictional force is acting on it. B) it is not acted on by appreciable gravitational force. C) a net upward force is acting on it. D) it is not acted on by appreciable normal force. E) a net downward force is acting on it. load and the bed is 0.40. The truck accelerates forward and the crate stays in its place on the truck bed. In what direction is the force that the bed exerts on the crate? A) backward B) forward C) toward the center of the road respect to the bed. D) There is no frictional force because the move with There is not enough information to answer this question. FIGURE 6-1 m Figure 6-1, the block of massm is at rest on an inclined plane that makes an anglee with the horizontal. The force of static frictionf must be such that A) f >ng sina. 4) A 50,0-kg bov is being pushed along a horizontal surface. The coefficient of kinetic friction for il between the box and the ground is 0.350. What horizontal force must be everted on the bov to accelerate at 1.20 m/s2? E) 172 N B) 491 N A) 116 N 50 A baseball player is running to second base at 5.03 m/s. When he is m from the plate he 50 4,80 goes into a slide. The coefficient of kinetic friction between the player and the ground is0.180. What is his speed when he reaches the plate? A) 196 m/s B) 2.56 m/s 4.47 m/s D) 289 m/s E) He stops before reaching the plate.

Explanation / Answer

1) since it doesnt speed up as it goes down it has to lose energy to friction so A)

2)

so friction is what keeps the cart in place

so it has to be forward

B)

3) since it stationary f = m g sin theta so C)

4)

F - firction = m a

F - u m g = m a

F = 0.35*50*9.81 + 50*1.2= 232 N

so D)

5)friction = m a

um g = m a

a = u g

v^2 = v0^2 + 2 a x

v^2 = 5.03^2 -2*0.18*9.81*4.8

v=2.89 m/s

so D)

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