You are exploring a planet and drop a small rock from the edge of a cliff. In co

Question

You are exploring a planet and drop a small rock from the edge of a cliff. In coordinates where the +y direction is downward and neglecting air resistance, the vertical displacement of an object released from rest is given by y ? y0 = 1/2gplanet(t)^2, where gplanet is the acceleration due to gravity on the planet. You measure "t" in seconds for several values of y ? y0 in meters and plot your data with t^2 on the vertical axis and y ? y0 on the horizontal axis. Your data is fit closely by a straight line that has slope 0.200 s^2/m. Based on your data, what is the value of gplanet?

I don't even know where to start :(

Explanation / Answer

so we can see that y-y0 = 1/2*g *t^2

so 2/g(y-y0) = t^2

so slope would be 2/g

so 2/g = 0.2

2 = 0.2 g

g = 2/0.2 = 10 m/s^2

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