6. A man who has type B blood and a woman who has type A blood could have childr

Question

6. A man who has type B blood and a woman who has type A blood could have children of which phenotypes? Explain your answer.

7. Unattached earlobes are a dominant trait. If A denotes the allele for unattached earlobes, and a denotes the allele for attached earlobes, what is (are) the possible genotype(s) of a person who has unattached earlobes? Could both parents of a person with unattached earlobes have attached earlobes? Why or why not?

8. What are the two main causes of heritable variation?

9. Give two examples in each case of (a) continuous, (b) discontinuous variation in human populations.

10. What name is given to an enzyme that is used to cut a DNA molecule at specific sites? What purpose do they serve?

Explanation / Answer

6. There are 4 possible ABO phenotypes. A, B, AB, and O. For type A phenotype you have AA or AO. For Type B phenotype you have BB and BO. If you make a punnet square matching up AA & BB, AA & BO, AO & BO, AO & BB. The phenotypes you get out of that are AB blood, B blood, A blood, and O blood.

7. For a person with unattached earlobes you would have possible geneotypes of AA and Aa since A is dominat for unattached earlobes. Two parents with unattached earlobes can have a child with attached earlobes because if the parents genotypes are Aa x Aa, when you have the punnet square for that cross your ratio will end up being 3:1. 3 children with unattached earlobes and one child with attached earlobes.

8. The two main causes of heritable variation are mutations and recombinations.

9. continous height and weight. Discontinous would be blood type

10. Restricion enzymes cut DNA at specific sites. The purpose they serve is to cut foreign DNA that may enter the cell (ie a virus.)

hope this helps you! goodluck!

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