Tap image to zoom Part A What is the net torque on the merry-go-round? Express y

Question

Tap image to zoom Part A What is the net torque on the merry-go-round? Express your answer to three significant figures and include the appropriate units. ? = SubmitGive Up Part B What is the net torque if Jerry reverses the direction that he pushes by 180? without changing the magnitude of his force? Express your answer to three significant figures and include the appropriate units. ? =
Part A What is the net torque on the merry-go-round? Express your answer to three significant figures and include the appropriate units. ? = SubmitGive Up Part A What is the net torque on the merry-go-round? Express your answer to three significant figures and include the appropriate units. ? = SubmitGive Up ? = ? = SubmitGive Up Part B What is the net torque if Jerry reverses the direction that he pushes by 180? without changing the magnitude of his force? Express your answer to three significant figures and include the appropriate units. ? =
Part B What is the net torque if Jerry reverses the direction that he pushes by 180? without changing the magnitude of his force? Express your answer to three significant figures and include the appropriate units. ? =
? =
? =
? = Tom and Jerry both push on the 3.00- m -diameter merry-go-round shown in . Tom pushes with a force of 51.0 N and Jerry pushes with a force of 32.5 N . Part A What is the net torque on the merry-go-round? Express your answer to three significant figures and include the appropriate units. ? = SubmitGive Up Part B What is the net torque if Jerry reverses the direction that he pushes by 180 ? without changing the magnitude of his force? Express your answer to three significant figures and include the appropriate units. ? =

Explanation / Answer

r = d/2= 3/2 = 1.5 m

A) Tnet = F_T*r*sin(60) - F_J*r*sin(80)

= 51*1.5*sin(60) - 32.5*1.5*sin(80)

= 18.24 N.m

B)

Tnet = F_T*r*sin(60) + F_J*r*sin(80)

= 51*1.5*sin(60) + 32.5*1.5*sin(80)

= 115.6 N.m

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