Given the two displacements Find the magnitude of the displacement 2D - E Consid

Question

Given the two displacements Find the magnitude of the displacement 2D - E Consider the vectors shown. What is the dot product C.D? (120 m2) cos 78.0 Degree (120 m2) sin 78.0 Degree (120 m2) cos 62.0 Degree (120 m2) sin 62.0 Degree none of these The angle Theta is measured counterclockwise from the positive x axis as shown. For which of these vector is theta greatest? Find the scalar product A B of the two vectors in the figure. The magnitude of the vectors are A = 4.00 and B = 5.00. Find the angle between the vectors A = 2.00 + 3.00 +1.00k and B =-4.00 + 2.00 -1.OOk

Explanation / Answer

1. 2D = 12i+6j-2k

2D-E = (12-4)i+(6+5)j+(-2-8)k =8i+11j-10k

l2D-El = 16.88

2. For Option D , theta is greatest = tan-1(4/3)=53.13

3. Option C : Dot product = lCl* lDl*cos(theta) = 12*10*cos(25+37) =120cos(620)

4. A.B = lAl*lBl*cos (theta) = 4*5*cos(130-53)= 20cos(770)

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