A baseball with a mass of 139 g is thrown horizontally with a speed of 39.0 m/s

Question

A baseball with a mass of 139 g is thrown horizontally with a speed of 39.0 m/s (87 mi/h) at a bat. The ball is in contact with the bat for 1.00 ms and then travels straight back at a speed of 45.9 m/s (103 mi/h). Determine the average force exerted on the ball by the bat. Neglect the weight of the ball (it is much smaller than the force of the bat) and choose the direction of the incoming ball to be positive. (Indicate the direction with the sign of your answer.)

I was able to find the answer as 959.1 N but that is not the correct answer.

Explanation / Answer

Using the impulse-momentum theorem:

F?t = ?p
F = ?p / ?t
= [mv(f) - mv(i)] / t
= m[v(f) - v(i)] / t
= 0.139kg(-45.9m/s - 39m/s) / 0.001s
= -11,801N

So the force of the ball on the bat is 11.8kN. Because of Newton

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