14. You are calculating the speed at which a dropped rock will hit the bottom of

Question

14. You are calculating the speed at which a dropped rock will hit the bottom of a deep well. Employing conservation of mechanical energy, you derive v =square root 2gd Here, d is the depth of the well and g is free fall acceleration. Let v1 be the speed for a well with a depth of d1. For a well that is half as deep the speed would be A) 3 x v1 B) square root 2 x v1 C) v1/square root 2 D) 4 x v1 E) 2 x v1 15. A roller coaster cart approaches a sequence of two hills, the second twice as high as the first. At the top of the first hill, the cart has slowed down to 75% of its initial speed. Which statement is correct? (Ignore friction.)

Explanation / Answer

d' =d1/2

v' = sqrt(2gd') = sqrt(2gd1/2)= sqrt(2gd1) / sqrt(2)

v' = v1 / sqrt(2)

option ": C

Related Questions

Navigate

• Browse (All)
• Browse 1
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.