An alpha particle ( q = +2 e , m = 4.00 u) travels in a circular path of radius

Question

An alpha particle (q = +2e, m = 4.00 u) travels in a circular path of radius 4.87 cm in a uniform magnetic field with B = 1.30 T. Calculate (a) its speed, (b)its period of revolution, (c) its kinetic energy, and (d) the potential difference through which it would have to be accelerated to achieve this energy.

(a) Number Units An alpha particle (q = +2e, m = 4.00 u) travels in a circular path of radius 4.87 cm in a uniform magnetic field with B = 1.30 T. Calculate (a) its speed, (b)its period of revolution, (c) its kinetic energy, and (d) the potential difference through which it would have to be accelerated to achieve this energy. (a) Number Units Units (d) Number Units (c) Number (b) Number

Explanation / Answer

qB=mv^2/r

q=2e

1.v=sqrt(rqB/m)

2.T=2*pi*r/v

3.KE=1/2*m*v^2

4.V=m*v^2/(2q)

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