Help please!!! Part F What would the answers to part (B) be if the proton were r

Question

Help please!!!

Part F

What would the answers to part (B) be if the proton were replaced by an electron traveling in the same way as the proton?

Find the magnitude of the force this magnetic field exerts on the proton. A proton traveling at 4.40km/s suddenly enters a uniform magnetic field of 0.800T , traveling at an angle of 55.0 degree with the field lines (see the figure (Figure ).If you can vary the direction of the proton's velocity, find the magnitude of the maximum and minimum forces you could achieve Answer the question in the order indicated. Separate your answers using comma.

Explanation / Answer

part B

Given:-

v= 4.40km/s
B=0.8T

?= 55o

q=+1.6*10-19C [charge of a proton]

FB= qvB sin?=1.6*10-19 * 4.40*103 *0.8* sin55o =4.61*10-16N

Part C

Force is maximum when ?=90o ,

F max= qvB sin?=1.6*10-19 * 4.40*103 *0.8* sin90o=5.63*10-16N

Force is minimum when ?=180o ,

F max= qvB sin?=1.6*10-19 * 4.40*103 *0.8* sin180o=0N

Part D

F is maximum when v is perpendicular to B ; Fis mimimum when v is either parallel or antiparallel to B.

Part E

Not sufficient data [part A not uploaded]

Part F

if the proton were replaced by an electron traveling in the same way as the proton

FB= qvB sin?=-1.6*10-19 * 4.40*103 *0.8* sin55o =-4.61*10-16N       [q=-1.6*10-19C [charge of a electron]

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