(1) The four tires on the author\'s car are inflated to an absolute pressure of
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Question
(1) The four tires on the author's car are inflated to an absolute pressure of 2.4 105 Pa. If the car has a mass of 2,300 kg, what is the contact area between each tire and the ground?
(2) A swimming pool of depth 2.8 m is filled with ordinary (pure) water (? = 1000 kg/m3).
please help!!!
(1) The four tires on the author's car are inflated to an absolute pressure of 2.4 105 Pa. If the car has a mass of 2,300 kg, what is the contact area between each tire and the ground? (2) A swimming pool of depth 2.8 m is filled with ordinary (pure) water (? = 1000 kg/m3). (a) What is the pressure at the bottom of the pool? (b) When the pool is filled with salt water, the pressure changes by 4.8 x 103 Pa. What is the difference between the density of the salt water and the density of pure water? kg/m3 please help!!!Explanation / Answer
(1)
if the vehicle is not accelerating, then the force of the pressure in the tires equals the weight of the cars
P = F/area so F = area x P
we are told the pressure is absolute pressure, which is the pressure in the tires (gauge pressure)+atmospheric; subtracting atmospheric pressure (which is 1.01x10^5PA), we have the pressure in the tires is 1.3x10^5Pa, so
A = 2300*9.8/1.3*10^5 = 0.17338 m^2
(2)
(a)
Pressure = Density x Gravity acceleration x Height
Density of water = 1000 Kgm^-3
Gravity acceleration = 9.8 ms^-2
Height = 2.8 m
Pressure = 1000 x 9.8 x 2.8 = 27440 Pa
(b) 4800 = rho * 9.8*2.8
rho = 174.93 kg/m^3
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