A uniform bar has two small balls glued to its ends. The bar is 2.40m long and w
ID: 1288083 • Letter: A
Question
A uniform bar has two small balls glued to its ends. The bar is 2.40m long and with mass 3.80kg , while the balls each have mass 0.700kg and can be treated as point masses.
Part A: Find the moment of inertia of this combination about an axis perpendicular to the bar through its center.
Part B: Find the moment of inertia of this combination about an axis perpendicular to the bar through one of the balls.
Part C: Find the moment of inertia of this combination about an axis parallel to the bar through both balls.
Explanation / Answer
a) I = 3.80 x 2.42/12 + 2 x 0.7 x (1.2)2
= 3.84 kg*m^2
b) I = 3.80 x 2.42/3 + 0.7 x 2.42
= 11.328 kg*m^2
c) I = 0
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