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A box of weight w=2.0N accelerates down a rough plane that is inclined at an ang

ID: 1288322 • Letter: A

Question

A box of weight w=2.0N accelerates down a rough plane that is inclined at an angle 30 degrees above the horizontal, as shown (Figure 6) . The normal force acting on the box has a magnitude n=1.7N, the coefficient of kinetic friction between the box and the plane is k=0.30, and the displacement of the box is 1.8 m down the inclined plane.

What is the work Ww done on the box by the weight of the box?

A box of weight w=2.0N accelerates down a rough plane that is inclined at an angle 30 degrees above the horizontal, as shown (Figure 6) . The normal force acting on the box has a magnitude n=1.7N, the coefficient of kinetic friction between the box and the plane is AA1/4k=0.30, and the displacement of the box is 1.8 m down the inclined plane. What is the work Ww done on the box by the weight of the box?

Explanation / Answer


Vertical distance = 1.8 sin 30 = 0.90 m
W = 2.0 N * 0.90 m = 1.80J