(a) The rms current in the circuit. I rms = A (b) The rms voltage drop across th

Question

(a) The rms current in the circuit.
Irms =  A

(b) The rms voltage drop across the resistor.
?VR, rms =  V

(c) The rms voltage drop across the capacitor.
?VC, rms =  V

(d) The phase angle for the circuit.
The voltage  - leads lags  the current by  .

A 54.0 ½F capacitor is connected to a 53.0 ohm resistor and a generator whose rms output is 30.0 V at 60.0 Hz. Find the following values: (a) The rms current in the circuit. Irms = A (b) The rms voltage drop across the resistor. ?VR, rms = V (c) The rms voltage drop across the capacitor. ?VC, rms = V (d) The phase angle for the circuit. The voltage - leads lags the current by ½.

Explanation / Answer

apacitive reactance

XC=1/2pi*f*C =1/2pi*60*(54*10-6) =49.12 ohms

Impedance

Z=sqrt[R2+Xc2]=72.26 ohms

a)

Rms Current

Irms=Vrms/Z =30/72.26 =0.415 A

b)

Vrms=Irms*R=0.415*53=22 Volts

c)

Vrms=Irms*Xc=0.415*49.12=20.4 Volts

d)

Phase angle

o=tan-1(-Xc/R) =--42.820

The voltage lags the current

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