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Vance Joy Riptic x VD Houses Soak x math.msu.edu/~m x Mail Inbox: Upco x V Mail Inbox: Hom x math.msuedu/~so X C Calculus Early Trai x V LON-CAPA Course x R ON-CAPA, Speed x k Help x x 7433bf64308C4abboa9a6fd 65 167b82 161e72f 1b5773050abe8ef60d92bee3ca7 b06436d2615c47f9e 7 6ae684f401429835302b02541 Q https: Messages Courses Help Logout Joseph Raymond Zajac v Stud section: 730) PHY 233B Fall 2014. Main Menu l contents Grades Course Contents HW #8 (11/06 Th 11:59 PM Speed of a satellite around the Earth Timer Notes Evaluate & Feedback Print Find the speed of a satellite in a circular orbit around the Earth with a radius 2.37 times the mean radius of the Earth. (Radius of Earth -6.37x103 km, mass of Earth 5.98x 10 24 kg, G 6.67 x 10 11 Nm2/kg2.) 6254 x10 0n5)m/ The gravitational force on the satellite provides the centripetal acceleration of the satellite Sub Answer Incorrect. Tries 4/12 Previous Tries Send Feedback EE Post Discussion 2:18 PM 11/4/2014Explanation / Answer
we will equate the earth's grav force to the centrip force acting on the satellite
GMm/r^2=mv^2/r
where M is the mass of the earth, v the speed of the satellite, r the distance from the center of the Earth, m the mass of the satellite, and G the newtonian grav cst
this gives us:
v^2=GM/r
v=sqrt[GM/r] =
sqrt[6.67x10^(-11)(5.98x10^24)/(2.37xR)] =
5140.07 m/s
(where R is the radius of the Earth=
6.37x10^6m)
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