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x f Mail Inbox: U x Mail Inbox: Ho x V math msu.edu x C Calculus Earl Tx C Vance Joy "Rip x OP Ma x math.msu.edu Panama LON-CAPA Co x ON-CAPA Plar x ON-CAPA Thre C question Che 5fa9182171259b8eda1952002e092a9ab27dS Q https: c/71/c14 d2 a79a5 df1 f57 f54e 8511d167 ca9 11 df6aab7e0087a828b139643edb157e346bae5 1dca5ca246ed65167b82161e72f513e2cb006ee6ecddeba0862bd 61d Messages Courses Help Logout Joseph Raymond Zajac v Stud section: 730) PHY 233B Fall 2014. Main Menu contents Grades Timer Notes Evaluate & Feedback Print Course Contents HW #8 (11/06 Th 11:59 PM Planet Glob 18 kg and a radius of 6.41x104 m. An astronaut on the surface of Glob throws a rock straight up. The The small spheric plane called "Glob" has a mass of 7.86x10 rock reaches a maximum height of 2.00x103 m, above the surface of the planet, before it falls back down. What was the initial speed of the rock as it left the astronaut's hand? (Glob has no atmosphere, so no energy is lost to air friction. G 6.67 x 10 11 Nm2/kg2.) Sub Answer Tries 0/12 A 29.0 kg satellite is in a circular orbit with a radius of 1.40x105 m around the planet Glob. Calculate the speed of the satellite Sub Answer Tries 0/12 Post Discussion Send Feedback 2:23 PM 11/4/2014

Explanation / Answer

1. g = GM / r^2

=6.67 * 10^-11 * 7.86 * 10^18 / ( 6.41 * 10^4)^2

= 1.27 / 10 = .127 m/ s^2

now

by energy balance

mgh = 1/2 mv^2

2gh = v^2

v^2 = 2 * 0.127 * 2 * 10^3 =508

v = 22.538 m/s

2. v = sqrt GM / R ; M = mass of planet, R= radius of orbit

= sqrt 6.67 * 10^-11 * 7.86 * 10^18 / 1.4 * 10^5

= 61.194 m/s

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