Let\'s pretend Uranium-236 can be regarded as a uniform sphere of charge +92e wi
ID: 1290854 • Letter: L
Question
Let's pretend Uranium-236 can be regarded as a uniform sphere of charge +92e with a radius of 7.4*10^-15m. In fission, it can divide into two "daughter" nuclei one half the charge and volume of the original nucleus. a) Find the radii of the two daughter nuclei. b) if we model this fission as the two daughter nuclei at rest and just touching, what kinetic energy will the daughters have when they are " very far" apart? c) if the energy you calculated in part(b) corresponds to one uranium atom, how much energy will be released by 10kg of uranium? ( The atomic mass of U-236 is 236 u, and 1u = 1.66*10^-27kg.) Let's pretend Uranium-236 can be regarded as a uniform sphere of charge +92e with a radius of 7.4*10^-15m. In fission, it can divide into two "daughter" nuclei one half the charge and volume of the original nucleus. a) Find the radii of the two daughter nuclei. b) if we model this fission as the two daughter nuclei at rest and just touching, what kinetic energy will the daughters have when they are " very far" apart? c) if the energy you calculated in part(b) corresponds to one uranium atom, how much energy will be released by 10kg of uranium? ( The atomic mass of U-236 is 236 u, and 1u = 1.66*10^-27kg.) a) Find the radii of the two daughter nuclei. b) if we model this fission as the two daughter nuclei at rest and just touching, what kinetic energy will the daughters have when they are " very far" apart? c) if the energy you calculated in part(b) corresponds to one uranium atom, how much energy will be released by 10kg of uranium? ( The atomic mass of U-236 is 236 u, and 1u = 1.66*10^-27kg.)Explanation / Answer
a) V Uranium = 4/3 pi r^2 = 4/3*pi*7.4E-15^3
0.5*4/3*pi*7.4E-15^3=4/3*pi*r^3
r=5.87E-15 m
b) Ei = Ef
k q Q/r = 2 KE
KE = 1/2 k qQ/r = 0.5*9.0E9*(92/2*1.6E-19)^2/(2*5.87E-15)=2.076E-11 J
c) E = KE*m total/mone atom = 2.076E-11*10/(236*1.66E-27)= 5.30E14 J
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