Need help with these two Sodium ions (Na^+) move at 0.794 m/s through a bloodstr

Question

Need help with these two

Sodium ions (Na^+) move at 0.794 m/s through a bloodstream in the arm of a person standing near a large magnet. The magnetic field has a strength of 0.26 T and makes an angle 71.2 degree with the motion of the sodium ions. The arm contains 75.9 cm^3 of blood (within the magnetic field) with 2.09 x 10^20 Na+-/cm^3. If no other ions were present in the arm, what would be the magnetic force on the arm? (Note: In fact, many oppositely charged ions also flow in the bloodstream, so the net force is considerably smaller than the number you will calculate here.)

Explanation / Answer

magnetic force = q ( v X B ) = 2.09 * 1020 * 75.9 ( 0.794 X 0.26 ) sin 71.2 = 30.97 * 1020N

Related Questions

Navigate

• Browse (All)
• Browse N
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.