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44% Sat 2:34 AM Q E 03 Safari File Edit View History Bookmarks Develop Window Help O O O HW 9 www.weba web/Studen ponses/last?dep 9175097 Q8 Reade gn.ne gnmen App ESPN Announcements Blackb destiny dlc Search Result... Causes of Diabetes Check An Object is d 61. HW 9 5. -1 points SerCP9 23. P.008 My Notes To fit a contact lens to a patient's eye, a keratometer can be used to measure the curvature of the cornea-the front surface of the eye. This instrument places an illuminated object of known size at a known distance p from the cornea, which then reflects some light from the object, forming an image of it. The magnification M of the image is measured by using a small viewing telescope that allows a comparison of the image formed by the cornea with a second calibrated image projected into the field of view by a prism arrangement. Determine the radius of curvature of the cornea when p cm and M 27.0 0.0130 mm Need Help? Read it Chat About It 6. -1 points SerCP9 23.P.021.soln My Notes A cubical block of ice 56.0 cm on an edge is placed on a level floor over a speck of dust. Locate the image of the speck, when viewed from directly above, if the index of refraction of ice is 1.309 cm below the upper surface of the ice Need Help? Read it Chat About It 7. -1 points SerCP9 23. P.022. My Notes A goldfish is swimming inside a spherical bowl of water having an index of refraction n 1.333. Suppose the goldfish is p 11.0 cm from the wall of a bowl of radius IRI 16.8 cm, as in the figure below. Neglecting the refraction of light caused by the wall of the bowl, determine the apparent distance of the goldfish from the wa according to an observer outside the bowl

Explanation / Answer

5.
We use the lens eqn 1/s + 1/s' = 2/R and M = -s'/s...Here s = 27.0 cm
So
s' = -M*s = -0.013*27.0 cm = -0.351 cm

Now
2/R = (1/27 + 1/(-0.351)) = -2.812

Therefore
R = 2/-2.812
R = -0.711 cm
Radius of curvature, R = -7.11 mm

6.
App.depth = (real depth) / (ref.index) = 56.0cm / 1.309
App.depth = 42.78 cm below the upper surface of ice

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