7.2 Problems 7) A 0.330-kg volleyball is thrown vertically downward with a speed
ID: 1294067 • Letter: 7
Question
7.2 Problems 7) A 0.330-kg volleyball is thrown vertically downward with a speed of 0.150 m/s in a place where g = 9.81 m/s^2. It takes it 0.0655 s to reach the ground. What is the magnitude of its momentum just before it hits the ground? A) 0.212 kg m/s B) 0.262 kg m/s C) 0.163 kg m/s D) 0.0216 kg m/s E) 0.0418 kg m/s 8) In a police ballistics test, 2.00-g bullet traveling at 700 m/s suddenly hits and becomes embedded in a stationary 5 00.kg wood block. What is the final speed of the combined block and bullet immediately following the collision? 9) A 328-kg car moving at 19.1 m/s in the +x direction hits from behind a second car moving at 130 m/s in the same direction. It the second car has a mass of 790 kg and a speed of 15.1 m/s right after the collision, what is the velocity of the first car after this sudden collision? A) 14.0 m/s B) 18.2 m/s C) 24.2 m/s D) -14.0 m/sExplanation / Answer
Number 7)
Find the velocity just before it hits the ground...
vf = vo + at
vf = (.150) + (9.81)(.0655)
vf = .793 m/s
p = mv
p = (.33)(.793)
p = .262 kg m/s (Choice B)
Number 8)
By conservation of momentum...
mv = (m + m)(v)
(.002)(700) = (5.002)(v)
v = .280 m/s
Number 9)
By conservation of momentum
mv + mv = mv + mv
(328)(19.1) + (790)(13) = (328)(v) + (790)(15.1)
v = 14.0 m/s (Choice A)
Related Questions
Hire Me For All Your Tutoring Needs
Integrity-first tutoring: clear explanations, guidance, and feedback.
Drop an Email at
drjack9650@gmail.com
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.