1. Consider a resistor of 10 ? tied parallel to a 1.5 V battery. The potential d
ID: 1295308 • Letter: 1
Question
1. Consider a resistor of 10 ? tied parallel to a 1.5 V battery. The potential drop across the resistor ideally should be ________________.
2. In the above scenario, the current through the resistor should ideally be ____________.
3. Suppose you measure the potential difference across a resistor using a voltmeter. Further suppose the reading you obtain is not even close to the ideal reading you were expecting. In fact, it is absurd. Assuming that there is nothing wrong with the meter and the settings on the meter were correct, and there are no issues with the lead wires and the circuit is certainly closed, a probable cause might be that:
a. You are measuring the voltage with the voltmeter in parallel with the resistor.
b. You are measuring the voltage with the voltmeter in series with the resistor.
c. The potential difference across the power source is not maintained.
d. The temperature of the resistor got too high in the measurement process.
4. Suppose you measure the current through a resistor using an ammeter. Further suppose the reading you obtain is not even close to the ideal reading you were expecting. In fact, it is absurd. Assuming that there is nothing wrong with the meter and the settings on the meter were correct, and there are no issues with the lead wires and the circuit is certainly closed, a probable cause might be that:
a. You are measuring the current with the meter in parallel with the resistor.
b. You are measuring the current with the meter in series with the resistor.
c. The potential difference across the power source is not maintained.
d. The temperature of the resistor got too high in the measurement process.
5. Suppose you have five equivalent resistors and a 1.5 V battery. You construct a single current loop with one resistor and measure a current of 0.1 A. Approximately what current would you measure if you connected all five of the resistors in that single current loop?
6. The most probable reason to linearize the equation of capacitance was to:
a. Predict the magnitude of charge on either plate.
b. Find a critical separation where the electric field vanishes.
c. Use the slope to find the permittivity.
d. Determine the strength of the field mid-way between the plates.
Explanation / Answer
1. 1.5 V
2. 0.15 A
3 B
4 A
5. 0.1A/5 =0.02 A
6 C
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