Print Icakulator Periodic Table Question 3 of 17 Incorrect sapling learning Dete

Question

Print Icakulator Periodic Table Question 3 of 17 Incorrect sapling learning Determine the image distance for an object db. 5.500 cm from a diverging lens of radius of arvature 4400 cm and index of refraction 1.750. (Express your answer as a positive quantity) R-4.400 cm object What is the magnification of the object? (Be sure to insert the proper sign if needed.) Number What is the nature of the image? O Inverted and smaller o upright and smaller O Inverted and larger O Upright and larger Previous ® Give Up & view solution 2 Check Answer o Next SExa

Explanation / Answer

1/f = (n-1)*((1/R1)-(1/R2))

R1 = -4.4 cm

R2 = +4.4 cm

1/f = (1.75-1)*(-2/4.4) = -0.341

1/do + 1/di = 1/f

1/5.5 + 1/di = 1/f

di = -1.913 cm

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m = -di/do = 0.3478

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m = + and less than 1

upright and smaller

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