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A 0.40 kg rock is placed in a slingshot and the rubber band is stretched . First

ID: 1296847 • Letter: A

Question

A 0.40 kg rock is placed in a slingshot and the rubber band is stretched . First a student measures the force needed to stretch the rubber band . the force of the rubber band on the rock is shown by the graph in the figure to the right. Is the rubber band stretched to the right or to the left? (left or right) Explain Does this rubber band obey Hooke's law? (yes or no) Explain (2 points) Using the values shown on the graph, calculate the rubber band's spring constant k in N/m? Now the rubber band is stretched 15 cm(=15 cm.) . What is the maximum potential energy PEmax, of stored in this system. What is the speed, v, of the rock as it leaves the slingshot when it is released?(4 points)

Explanation / Answer


a)
left
because force F is positive and elongation x is negative

b)
yes
for the graph slope is constant

c)
k=F/x
=20/10
=2 N/cm
=200 N/m

d)
U=1/2*kx^2
=1/2*200*0.15^2
=2.25 J

e)

1/*mv^2=1/2KX^2
1/2*mv^2=2.25
1/2*0.04*v^2=2.25
===>
v=10.6 m/sec