(8c32p7) Suppose that a parallel-plate capacitor has circular plates with radius
ID: 1298306 • Letter: #
Question
(8c32p7) Suppose that a parallel-plate capacitor has circular plates with radius R = 70.0 mm and a plate separation of 4.3 mm. Suppose also that a sinusoidal potential difference with a maximum value of 260 V and a frequency of 60 Hz is applied across the plates; that is
V=(260.0 V)sin((2.*?)*(60 Hz * t)).
a) Find Bmax(R), the maximum value of the induced magnetic field that occurs at r = R.
b) Find B(r = 35.0 mm).
c) Find B(r = 140.0 mm).
d) Find B(r = 210.0 mm).
I've spent quite a long time on this, help is much appreciated!
Explanation / Answer
I have solved this question earlier with different figures. Please workout using yours figures. If you need any further help just PM me. If I have helped you please rate me 5 stars first (before you rate anyone else)
Suppose that a parallel-plate capacitor has circular plates with radius R = 35.0 mm and a plate separation of 4.1 mm. Suppose also that a sinusoidal potential difference with a maximum value of 160 V and a frequency of 60 Hz is applied across the plates; that is
V=(160.0 V)sin((2.*p)*(60 Hz * t)).
Find Bmax(R), the maximum value of the induced magnetic field that occurs at r = R.
Find B(r = 17.5 mm).
Find B(r = 70.0 mm).
Find B(r = 105.0 mm).
Answer
Here radius of the circular plates is R = 35 mm = 35*10-3m
seperation between the plates is d = 4.1 mm = 4.1*10-3m
frequency of voltage f = 60 Hz
Then angular frequency ? = 2?f = 2?*60 rad/sec
We know that magnetic field between the plates when r < = R is
Bin=(?0?0r/2)dE/dt
E = V/d
Then Bin=(?0?0r/2d)dV/dt
Here V = ( Vmax) sin?t
dV/dt = ( Vmax)?cos?t
dV/dt = (160 V) cos[2?(60 Hz)t]*2?(60Hz)
?0= 4?*10-7H/m
?0= 8.85*10-12C2/Nm2
Here Vmax = 160 V
This grows until r = R = 35 mm = 0.035 m
Then Bmax =(?0?0R?/2d)Vmax
= [(4?*10-7H/m) * (8.85*10-12C2/Nm2)* 0.035 m *(2?*60 rad/sec )/2* 4.1 *10-3m]*160Volts
= 2.86 *10-12T
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.