a spring with spring comstany k=15 n/m hangs vertically from the ceiling. a 1.2
ID: 1299176 • Letter: A
Question
a spring with spring comstany k=15 n/m hangs vertically from the ceiling. a 1.2 kg mass is attachrf to the bottom end of the spring and allowed to hamg freely until it becomes stationary. then the mass is pulled dpwnward 10 cm from its resting position to release.. at the moment of release what is magnitude of mass acceleration and direction? a spring with spring comstany k=15 n/m hangs vertically from the ceiling. a 1.2 kg mass is attachrf to the bottom end of the spring and allowed to hamg freely until it becomes stationary. then the mass is pulled dpwnward 10 cm from its resting position to release.. at the moment of release what is magnitude of mass acceleration and direction?Explanation / Answer
we know that the restoring force ,
F = -kx ----------------- (1)
here - sign indicates opposite direction
according to newton's 2nd law of motion,
F = ma ---------------- (2)
from equations (1) & (2)
a = (k/m)x
a = (15/1.2)10*10^-2
a = 1.25 m/s^2
the magnitude of the mass's acceleration 1.25 m/s^2.
the direction is upwards.
the direction is upwards.
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