Jack was exposed to fast neutrons; he received a radiation dose of 160rem on par

Question

Jack was exposed to fast neutrons; he received a radiation dose of 160rem on part of his hand, affecting 22.0grams of tissue. The relative biological effectiveness (RBE) of these neutrons is 8.00.

Part A

How much radiation did Jack receive?

Express your answer in rads to three significant figures.

Part B

What was the total energy of the radiation Jack received?

Express your answer in joules to three significant figures.

Part C

Suppose Jill received the same rad dosage, but from beta rays with an RBE of 1.40 instead of from neutrons. What is the value of the equivalent dose she received?

Express your answer in rems to three significant figures.

Explanation / Answer

GIven

Radiation dose = 160 rem

Mass of tissue , m = 22 g = 0.022 kg

RBE of neutrons = 8

The radiation received by Jack = Biological dose equivalent (BDE) / RBE --1

                                               = 160 rem / 8

                                                = 20 rad

Since 1 rad = 0.01 J / kg

So, 20 rad = 0.01 * 20 J / kg = 0.20 J / kg

The total energy of radiation received by Jack = 0.20 J * 0.022 kg /kg = 4.4 *10^-3 J

For Jill

Absorbed radiation dosage = 20 rad

RBE = 1.40

BDE = (Absorbed radiation dosage )* RBE [From eq 1]

        = 20 rad * 1.40 = 28 rem

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