1) An unknown material experiences an alpha decay and a beta decay. The end prod
ID: 1301978 • Letter: 1
Question
1) An unknown material experiences an alpha decay and a beta decay. The end product is an element with 48 protons and a total of 112 nucleons. Calculate the original atomic number and atomic mass of the original material before the decays. atomic number=Answer atomic mass=Answer
2)
On the sun, the nuclei of four ordinary hydrogen atoms combine to form a helium isotope, 2He4. This reaction is called nuclear fusion. How many of what types of particles are missing from the nuclear equation listed below?
4(1H1)?2He4 + ?
Missing particle name?Answer
How many? Answer
Explanation / Answer
10
atomic number = 112/2 = 66
atonic mass = 112amu
2)
4 (1H)+ 2 e --> 4He + 2 neutrinos + 6 photons
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.