9. 0 /1 points | Previous Answers OSColPhys1 31.7.078. My Notes | Question Part

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9.0/1 points |  Previous AnswersOSColPhys1 31.7.078.My Notes  | Question Part Points Submissions Used A 7.00 T magnetic field is applied perpendicular to the path of charged particles in a bubble chamber. What is the radius of curvature of the path of a 10.8 MeV proton in this field? Neglect any slowing along its path. 9.0/1 points |  Previous AnswersOSColPhys1 31.7.078.My Notes  | 9.0/1 points |  Previous AnswersOSColPhys1 31.7.078.My Notes  | Question Part Points Submissions Used A 7.00 T magnetic field is applied perpendicular to the path of charged particles in a bubble chamber. What is the radius of curvature of the path of a 10.8 MeV proton in this field? Neglect any slowing along its path. Question Part Points Submissions Used Question Part Points Submissions Used Question Part Points Submissions Used Question Part Points Submissions Used Question Part Points Submissions Used A 7.00 T magnetic field is applied perpendicular to the path of charged particles in a bubble chamber. What is the radius of curvature of the path of a 10.8 MeV proton in this field? Neglect any slowing along its path. A 7.00 T magnetic field is applied perpendicular to the path of charged particles in a bubble chamber. What is the radius of curvature of the path of a 10.8 MeV proton in this field? Neglect any slowing along its path. Question Part Points Submissions Used

Explanation / Answer

E = 1/2 m v2

v = sqrt [2E / m]

= sqrt [ 2 * 10.8 MeV / 938.27 MeV/c2]

= 0.1517 * 3 * 108

= 4.55 * 107 m/s

r = m v / q B

= 1.67 * 10-27 * 4.55 * 107 / (1.6 * 10-19 * 7.00)

= 0.0678 m = 6.78 cm

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