I can\'t figure out the last question of this: A hydraulic lift has two connecte

Question

I can't figure out the last question of this:

A hydraulic lift has two connected pistons with cross-sectional areas 15 cm2 and 630 cm2. It is filled with oil of density 500 kg/m3.

1)What mass must be placed on the small piston to support a car of mass 103 kg at equal fluid levels?

m =

23.8 kg  

2)With the lift in balance with equal fluid levels, a person of mass 60 kg gets into the car. What is the equilibrium height difference in the fluid levels in the pistons?

?h =

1.904 m  

3)How much did the height of the car drop when the person got in the car?

h =

????? m  

Explanation / Answer

volume displaces is the same in both pistons:
A1*h1 = A2*h2
A1*(H - h2) = A2*h2
A1*H = h2*(A1 + A2)
h2 = H*{A1/(A1+A2)}
h2 = 1.904 m (15 cm

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