The diagram shows an RL circuit with a switch. E=110V, R1=10 ohm, R2=43 ohm, R3=

Question

The diagram shows an RL circuit with a switch. E=110V, R1=10 ohm, R2=43 ohm, R3=58 ohm, and L=5H.

*All answers in A

1. The switch has been closed and after waiting a long time it is opened. What is I1 just after this opening?

2. What is I1 a very long time after the switch is closed?

3. What is I1 just after the switch is closed?

4. The switch has been closed and after waiting a long time it is opened. What is I1 a very long time after the switch is opened?

5. The switch has been closed and after waiting a long time it is opened. What is I1 just after this opening?

6. What is I2 a very long time after the switch is closed?

7. The switch has been closed and after waiting a long time it is oepend. What is I1 a very long time after the switch is opened?

8. What is I2 just after the switch is closed?

Explanation / Answer

The diagram shows an RL circuit with a switch. E=110V, R1=10 ohm, R2=43 ohm, R3=58 ohm, and L=5H.

*All answers in A

1. The switch has been closed and after waiting a long time it is opened. What is I1 just after this opening?

steady state achieved for inductor and switch opened.. inductor , resistors form a series circuit after switch is opened and inductor does not allow sudden changes in current so

steady state current = E/R2 = 110/43 = 2.558 amps

current I1 = -2.558 amps (series circuit and opposite direction to I2)

2. What is I1 a very long time after the switch is closed?

steady state achieved for inductor so

current I1 = E/R1 = 110/10 = 11 A

3. What is I1 just after the switch is closed?

just after switch is closed

inductor is open circuited and I1 = E/R1 = 110/10 = 11 A

4. The switch has been closed and after waiting a long time it is opened. What is I1 a very long time after the switch is opened?

I1 a very long time after the switch is opened = zero (inductor fully discharged)

5. The switch has been closed and after waiting a long time it is opened. What is I2 just after this opening?

I2 = 2.558 amp as calculated in 1st problem

6. What is I2 a very long time after the switch is closed?

steady state current = E/R2 = 110/43 = 2.558

7. The switch has been closed and after waiting a long time it is oepend. What is I2 a very long time after the switch is opened?

I2 after complete discharge very long time after the switch is opened = zero

8. What is I2 just after the switch is closed?

I2 = zero (sudden change in current not allowed in inductor so current is zero.. inductor acts as open circuit just after switch is closed)

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