Consider a fluorescent molecule where the electron that participates in fluoresc

Question

Consider a fluorescent molecule where the electron that participates in fluorescence has ground state energy of -4.6 eV. When the molecule is illuminated with light this electron is excited up to a state with energy -2.3 eV. When the electron is in the excited state excess charge will accumulate at points in the molecule. If the fluorescent is in a polar solvent (like water) the solvent can help stabilize the excited state. If the excited state has an energy of -2.6 eV when the fluorescent molecule is in water, what is the wavelength of the emitted photons?

Explanation / Answer

energy emitted = hc/ lambda = energy absorbed by photom

or, 2 *1.6*10^-19 = 6.6*10^-34 * 3*10^8 / lambda

so, lambda = wavelength of the emitted photons = 4.67 * 10^-7 m

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