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Your Last name: Your first name: Without formulae and proper explicit units, you

ID: 1307068 • Letter: Y

Question

Your Last name: Your first name: Without formulae and proper explicit units, you will get ZERO, even if the answer is correct! 1.20 points. A proton at rest is put inside a uniform vertical electric field of magnitude E. What magnitude electric field in N/C must be used in order to move upward the proton by 20 cm in one second? Is E upward or downward? 2. 20 points. What is the density of charge in C/cm2(NOT in C/m2) on the external surface of a conductor where the magnitude of the electric field is 10 V/cm (NOT in V/m)? Hint: 1 V/m is identical to 1 N/C

Explanation / Answer

1) qe-mg=ma

1/2at^2 =20*10^-2

a=40*10^-2=0.4 m/s^2

force eqn

1.6*10^-19*E -1.67*10^-27 g=1.67*10^-27*0.4

E=1.67*10^-27(9.8+0.4)/1.6*10^-19

= 10.64*10^-8N/C

2)CHARGE DENSITY/e0 =10

charge density= 10*8.8*10^-12/10^2 c/cm2 (e0=8.8*10^-12c/vm)

=8.8*10^-13 c/cm2

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