010 (part 1 of 2) 10.0 points The top of a swimming pool is at ground level. If

Question

010 (part 1 of 2) 10.0 points The top of a swimming pool is at ground level. If the pool is 4.5 m deep, how far below ground level does the bottom of the pool have to be located when the pool is completely filled with water? Answer in units of m.

011 (part 2 of 2) 10.0 points
How far below ground level does the bottom
of the pool appear to be located when the
pool is ?lled halfway with water?
Answer in units of m

The magnification produced by a converging lens is found to be -3.21 for an object placed 0.233 m from the lens. What is the focal length of the lens? Answer in units of m The left face of a biconvex lens has a radius of curvature of 19.2 cm. and the right face has a radius of curvature of 25.4 cm. The index of refraction of the glass is 1.44. Calculate the focal length of the lens. Answer in units of cm Calculate the focal length if the radii of curvature of the two faces are interchanged. Answer in units of cm A converging lens is placed 20.7 cm to the right of a diverging lens of focal length 26.1 cm. A beam of parallel light enters the diverging lens from the left, and the beam is again parallel when it emerges from the converging lens. Calculate the focal length of the converging lens. Answer in units of cm

Explanation / Answer

1) n1/S + nb/S' = 0

1.33/4.5 + 1/S' = 0

S' = - 4.5/1.33 = - 3.38 m

b)

part2

if half is filled

1.33/(2.25) + 1/S' = 0

S' = -1.69

from ground d = 2.25 + lS'l = 2.25+1.69 = 3.94 m

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2) m = -S'/S = -3.21

S' = 3.2 S = 3.2*0.233 = 0.7456 m

1/S + 1/S' =1/F

F = 0.177 m

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3) 1/F = (n-1)*((1/R1)_(1/R2))

1/F = (1.41-1)*((1/19.2)-(1/25.4))

F = 191.84 cm

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4) 1/F = (n-1)*((1/R1)_(1/R2))

1/F = (1.41-1)*((1/25.4)-(1/19.2))

F = -191.84 cm

=======================

5) F = d+f = 20.7 + 26.1 = 46.8 cm

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