help me! :) A two-turn circular wire loop of radius 0.733 m lies in a plane perp
ID: 1307770 • Letter: H
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help me! :)
A two-turn circular wire loop of radius 0.733 m lies in a plane perpendicular to a uniform magnetic field of magnitude 0.635 T. If the entire wire Ls reshaped from h two-turn circle to h one-turn circle in 0.102 s (while remaining in the same plane), what Ls the magnitude of the average induced emf e in the wire during this time? Use Faraday's law In a model generator, a 570-turn rectangular coil 0.074 m l»y 0.17 m rotates with an angular frequency of 12.6 rad/s in a uniform magnetic field of 0.53 T. What is the maximum emf induced in the coil? An AC generator consists of 40 turns of wire with an area of 0.12 m2. The loop rotates in a magnetic field of 0.119 T at a constant frequency of 27.9 Hz. The generator is connected across a circuit load with a total resistance of 33 Q. Find the maximum emf induced by the generator. Find the maximum induced current. Answer in units of AExplanation / Answer
1.induced emf e = NBdA/dt
initail area A = pir^2 = 3.14* 0.733 * 0.733 = 1.687 m^2
when convterted into one turn , total length = 2*2*3.14* 0.733
L = 2pi r = 9.206 m
r = 9.206/2pi
r = 1.466 m
area A = 3.14* 1.466*1.466 = 6.748 m^2
so change of area = 6.748 -1.687 = 5.061 m^2
so now induced emf e = 5.061* 0.635/0.102
emf e = 31.50 volts
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0.16:
induced emf e = NABW
e = 570* 0.074*0.17*12.6* 0.53
e = 47.88 volts
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0.17 :
induced emf e = NABW
W = 2pif
emf e = 40 * 0.12* 0.119 * *2*3.14* 27.9
emfe = 100.08 volts
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induced current i = emf/R = 100.08/33 = 3.03 Amps
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