Assume the absolute zero apparatus is initially open to the air. a) Assume that

Question

Assume the absolute zero apparatus is initially open to the air.

a) Assume that air pressure is Po = 1.00 atm and the air temperature is To = 16.4o C. How many moles of air will the sphere hold?
nair =   moles

b) Suppose now that the apparatus, initially open, is sealed with the air inside. If the apparatus is now heated to to 685o C, find the pressure inside the apparatus now.
P =  Pa

c) Assume now that the sphere is injected with another 0.0392 moles of air, and the temperature (685o C) is maintained. What is the new pressure inside the ball?
P =  Pa

Explanation / Answer

radius of sphere in apparatus = 0.0508 m

Volume of sphere(V) = 5.4914*10^-4 m^3

a) Po = 1.00 atm = 101325 Pa

To = 16.4 C = 289.55 K

nair = PV/RT = 101325*5.4914*10^-4/(8.314*289.55) = 0.0231 moles

b) T = 685 C = 958.15 K

new P = ?

since all other are constant so,

Po/To = P/T => P = 101325*958.15/289.55 = 335294.5907 Pa

c) nair = 0.0231 + 0.0392 = 0.0623 moles

New pressure = nRT/V = 0.0623*8.314*958.15/(5.4914*10^-4) = 903750.3768 Pa

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